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1/5x-9=2x
We move all terms to the left:
1/5x-9-(2x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-2x+1/5x-9=0
We multiply all the terms by the denominator
-2x*5x-9*5x+1=0
Wy multiply elements
-10x^2-45x+1=0
a = -10; b = -45; c = +1;
Δ = b2-4ac
Δ = -452-4·(-10)·1
Δ = 2065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2065}}{2*-10}=\frac{45-\sqrt{2065}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2065}}{2*-10}=\frac{45+\sqrt{2065}}{-20} $
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