32=7(y+2)-4y

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Solution for 32=7(y+2)-4y equation: 



32=7(y+2)-4y

We move all terms to the left:

32-(7(y+2)-4y)=0



We calculate terms in parentheses: -(7(y+2)-4y), so:

7(y+2)-4y

We add all the numbers together, and all the variables

-4y+7(y+2)

We multiply parentheses

-4y+7y+14

We add all the numbers together, and all the variables

3y+14

Back to the equation:

-(3y+14)



We get rid of parentheses

-3y-14+32=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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