1/4(2x-6)+3x=16

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Solution for 1/4(2x-6)+3x=16 equation: 



1/4(2x-6)+3x=16

We move all terms to the left:

1/4(2x-6)+3x-(16)=0



Domain of the equation: 4(2x-6)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/4(2x-6)-16=0

We multiply all the terms by the denominator


3x*4(2x-6)-16*4(2x-6)+1=0

Wy multiply elements

12x^2(2-64x(2+1=0

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