32=10+2(z-1)

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Solution for 32=10+2(z-1) equation: 



32=10+2(z-1)

We move all terms to the left:

32-(10+2(z-1))=0



We calculate terms in parentheses: -(10+2(z-1)), so:

10+2(z-1)

determiningTheFunctionDomain
2(z-1)+10

We multiply parentheses

2z-2+10

We add all the numbers together, and all the variables

2z+8

Back to the equation:

-(2z+8)



We get rid of parentheses

-2z-8+32=0

We add all the numbers together, and all the variables

-2z+24=0

We move all terms containing z to the left, all other terms to the right

-2z=-24

z=-24/-2

z=+12

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