(100/x+2)(x+4)=0

Solution for (100/x+2)(x+4)=0 equation:

(100/x+2)(x+4)=0


Domain of the equation: x+2)(x+4)!=0

x∈R


We multiply parentheses ..

(+100x^2+400x+2x+8)=0

We get rid of parentheses

100x^2+400x+2x+8=0

We add all the numbers together, and all the variables

100x^2+402x+8=0

a = 100; b = 402; c = +8;
Δ = b2-4ac
Δ = 4022-4·100·8
Δ = 158404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{158404}=398$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(402)-398}{2*100}=\frac{-800}{200}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(402)+398}{2*100}=\frac{-4}{200}
=-1/50
$