329=7(1+6b)

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Solution for 329=7(1+6b) equation: 



329=7(1+6b)

We move all terms to the left:

329-(7(1+6b))=0

We add all the numbers together, and all the variables

-(7(6b+1))+329=0



We calculate terms in parentheses: -(7(6b+1)), so:

7(6b+1)

We multiply parentheses

42b+7

Back to the equation:

-(42b+7)



We get rid of parentheses

-42b-7+329=0

We add all the numbers together, and all the variables

-42b+322=0

We move all terms containing b to the left, all other terms to the right

-42b=-322

b=-322/-42

b=7+2/3

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