3(y-1)=13-2(y+3)

Solution for 3(y-1)=13-2(y+3) equation:

3(y-1)=13-2(y+3)

We move all terms to the left:

3(y-1)-(13-2(y+3))=0

We multiply parentheses

3y-(13-2(y+3))-3=0


We calculate terms in parentheses: -(13-2(y+3)), so:

13-2(y+3)

determiningTheFunctionDomain
-2(y+3)+13

We multiply parentheses

-2y-6+13

We add all the numbers together, and all the variables

-2y+7

Back to the equation:

-(-2y+7)


We get rid of parentheses

3y+2y-7-3=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2