2(3x-4)=3(2x+5)+3x-6

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Solution for 2(3x-4)=3(2x+5)+3x-6 equation:



2(3x-4)=3(2x+5)+3x-6
We move all terms to the left:
2(3x-4)-(3(2x+5)+3x-6)=0
We multiply parentheses
6x-(3(2x+5)+3x-6)-8=0
We calculate terms in parentheses: -(3(2x+5)+3x-6), so:
3(2x+5)+3x-6
We add all the numbers together, and all the variables
3x+3(2x+5)-6
We multiply parentheses
3x+6x+15-6
We add all the numbers together, and all the variables
9x+9
Back to the equation:
-(9x+9)
We get rid of parentheses
6x-9x-9-8=0
We add all the numbers together, and all the variables
-3x-17=0
We move all terms containing x to the left, all other terms to the right
-3x=17
x=17/-3
x=-5+2/3

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