7+y=2(y+3)+2

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Solution for 7+y=2(y+3)+2 equation: 



7+y=2(y+3)+2

We move all terms to the left:

7+y-(2(y+3)+2)=0



We calculate terms in parentheses: -(2(y+3)+2), so:

2(y+3)+2

We multiply parentheses

2y+6+2

We add all the numbers together, and all the variables

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

y-2y-8+7=0

We add all the numbers together, and all the variables

-1y-1=0

We move all terms containing y to the left, all other terms to the right

-y=1

y=1/-1

y=-1

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