320=2l+2(2/3l)

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Solution for 320=2l+2(2/3l) equation: 



320=2l+2(2/3l)

We move all terms to the left:

320-(2l+2(2/3l))=0



Domain of the equation: 3l))!=0

l!=0/1

l!=0

l∈R



We add all the numbers together, and all the variables

-(2l+2(+2/3l))+320=0

We multiply all the terms by the denominator


-(2l+2(+2+320*3l))=0



We calculate terms in parentheses: -(2l+2(+2+320*3l)), so:

2l+2(+2+320*3l)

We add all the numbers together, and all the variables

2l+2(320*3l+2)

We multiply parentheses

2l+1920l+4

We add all the numbers together, and all the variables

1922l+4

Back to the equation:

-(1922l+4)



We get rid of parentheses

-1922l-4=0

We move all terms containing l to the left, all other terms to the right

-1922l=4

l=4/-1922

l=-2/961

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