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32-(2c+3)=2(c+4)+c
We move all terms to the left:
32-(2c+3)-(2(c+4)+c)=0
We get rid of parentheses
-2c-(2(c+4)+c)-3+32=0
We calculate terms in parentheses: -(2(c+4)+c), so:We add all the numbers together, and all the variables
2(c+4)+c
We add all the numbers together, and all the variables
c+2(c+4)
We multiply parentheses
c+2c+8
We add all the numbers together, and all the variables
3c+8
Back to the equation:
-(3c+8)
-2c-(3c+8)+29=0
We get rid of parentheses
-2c-3c-8+29=0
We add all the numbers together, and all the variables
-5c+21=0
We move all terms containing c to the left, all other terms to the right
-5c=-21
c=-21/-5
c=4+1/5
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