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-15+2x=7/8x-15
We move all terms to the left:
-15+2x-(7/8x-15)=0
Domain of the equation: 8x-15)!=0We get rid of parentheses
x∈R
2x-7/8x+15-15=0
We multiply all the terms by the denominator
2x*8x+15*8x-15*8x-7=0
Wy multiply elements
16x^2+120x-120x-7=0
We add all the numbers together, and all the variables
16x^2-7=0
a = 16; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·16·(-7)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{7}}{2*16}=\frac{0-8\sqrt{7}}{32} =-\frac{8\sqrt{7}}{32} =-\frac{\sqrt{7}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{7}}{2*16}=\frac{0+8\sqrt{7}}{32} =\frac{8\sqrt{7}}{32} =\frac{\sqrt{7}}{4} $
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