31=3y+7(y+3)

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Solution for 31=3y+7(y+3) equation: 



31=3y+7(y+3)

We move all terms to the left:

31-(3y+7(y+3))=0



We calculate terms in parentheses: -(3y+7(y+3)), so:

3y+7(y+3)

We multiply parentheses

3y+7y+21

We add all the numbers together, and all the variables

10y+21

Back to the equation:

-(10y+21)



We get rid of parentheses

-10y-21+31=0

We add all the numbers together, and all the variables

-10y+10=0

We move all terms containing y to the left, all other terms to the right

-10y=-10

y=-10/-10

y=1

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