4(r+20)=1/5(20r+40

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Solution for 4(r+20)=1/5(20r+40 equation:



4(r+20)=1/5(20r+40
We move all terms to the left:
4(r+20)-(1/5(20r+40)=0
Domain of the equation: 5(20r+40)!=0
r∈R
We multiply parentheses
4r-(1/5(20r+40)+80=0
We multiply all the terms by the denominator
4r*5(20r+40)+80-(1=0
We add all the numbers together, and all the variables
4r*5(20r+40)=0
Wy multiply elements
20r^2(2=0

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