30x^2+49x-20=0

Solution for 30x^2+49x-20=0 equation:

30x^2+49x-20=0

a = 30; b = 49; c = -20;
Δ = b2-4ac
Δ = 492-4·30·(-20)
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{4801}}{2*30}=\frac{-49-\sqrt{4801}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{4801}}{2*30}=\frac{-49+\sqrt{4801}}{60}
$