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30=9-3(x+2)
We move all terms to the left:
30-(9-3(x+2))=0
We calculate terms in parentheses: -(9-3(x+2)), so:We get rid of parentheses
9-3(x+2)
determiningTheFunctionDomain -3(x+2)+9
We multiply parentheses
-3x-6+9
We add all the numbers together, and all the variables
-3x+3
Back to the equation:
-(-3x+3)
3x-3+30=0
We add all the numbers together, and all the variables
3x+27=0
We move all terms containing x to the left, all other terms to the right
3x=-27
x=-27/3
x=-9
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