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(1/4)(16a-12)+5=33
We move all terms to the left:
(1/4)(16a-12)+5-(33)=0
Domain of the equation: 4)(16a-12)!=0We add all the numbers together, and all the variables
a∈R
(+1/4)(16a-12)+5-33=0
We add all the numbers together, and all the variables
(+1/4)(16a-12)-28=0
We multiply parentheses ..
(+16a^2+1/4*-12)-28=0
We multiply all the terms by the denominator
(+16a^2+1-28*4*-12)=0
We get rid of parentheses
16a^2+1-12-28*4*=0
We add all the numbers together, and all the variables
16a^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{32}=0$
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