30=8+(1-t)-2

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Solution for 30=8+(1-t)-2 equation: 



30=8+(1-t)-2

We move all terms to the left:

30-(8+(1-t)-2)=0

We add all the numbers together, and all the variables

-(8+(-1t+1)-2)+30=0



We calculate terms in parentheses: -(8+(-1t+1)-2), so:

8+(-1t+1)-2

determiningTheFunctionDomain
(-1t+1)+8-2

We add all the numbers together, and all the variables

(-1t+1)+6

We get rid of parentheses

-1t+1+6

We add all the numbers together, and all the variables

-1t+7

Back to the equation:

-(-1t+7)



We get rid of parentheses

1t-7+30=0

We add all the numbers together, and all the variables

t+23=0

We move all terms containing t to the left, all other terms to the right

t=-23

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