15-3/4x=13-1/2x

Solution for 15-3/4x=13-1/2x equation:

15-3/4x=13-1/2x

We move all terms to the left:

15-3/4x-(13-1/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3/4x-(-1/2x+13)+15=0

We get rid of parentheses

-3/4x+1/2x-13+15=0

We calculate fractions


(-6x)/8x^2+4x/8x^2-13+15=0

We add all the numbers together, and all the variables

(-6x)/8x^2+4x/8x^2+2=0

We multiply all the terms by the denominator


(-6x)+4x+2*8x^2=0

We add all the numbers together, and all the variables

4x+(-6x)+2*8x^2=0

Wy multiply elements

16x^2+4x+(-6x)=0

We get rid of parentheses

16x^2+4x-6x=0

We add all the numbers together, and all the variables

16x^2-2x=0

a = 16; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·16·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*16}=\frac{0}{32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*16}=\frac{4}{32}
=1/8
$