300/x=40-2x

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Solution for 300/x=40-2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

300/x = 40-(2*x) // - 40-(2*x)

2*x+300/x-40 = 0

2*x^1+300*x^-1-40*x^0 = 0

(2*x^2-40*x^1+300*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-40*x^1+300*x^0) = 0

x^1

2*x^2-40*x+300 = 0

2*x^2-40*x+300 = 0

DELTA = (-40)^2-(2*4*300)

DELTA = -800

DELTA < 0

x in { } 

x belongs to the empty set

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