(1-v)(4+2v)=0

Solution for (1-v)(4+2v)=0 equation:

Simplifying
(1 + -1v)(4 + 2v) = 0

Multiply (1 + -1v) * (4 + 2v)
(1(4 + 2v) + -1v * (4 + 2v)) = 0
((4 * 1 + 2v * 1) + -1v * (4 + 2v)) = 0
((4 + 2v) + -1v * (4 + 2v)) = 0
(4 + 2v + (4 * -1v + 2v * -1v)) = 0
(4 + 2v + (-4v + -2v2)) = 0

Combine like terms: 2v + -4v = -2v
(4 + -2v + -2v2) = 0

Solving
4 + -2v + -2v2 = 0

Solving for variable 'v'.

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + -1v + -1v2) = 0

Factor a trinomial.
2((1 + -1v)(2 + v)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + -1v)' equal to zero and attempt to solve:

Simplifying
1 + -1v = 0

Solving
1 + -1v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1v = 0 + -1
-1v = 0 + -1

Combine like terms: 0 + -1 = -1
-1v = -1

Divide each side by '-1'.
v = 1

Simplifying
v = 1
Subproblem 2
Set the factor '(2 + v)' equal to zero and attempt to solve:

Simplifying
2 + v = 0

Solving
2 + v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + v = 0 + -2

Combine like terms: 2 + -2 = 0
0 + v = 0 + -2
v = 0 + -2

Combine like terms: 0 + -2 = -2
v = -2

Simplifying
v = -2
Solution
v = {1, -2}