300+.014x=200+.025x(.011x)=100

Solution for 300+.014x=200+.025x(.011x)=100 equation:

300+.014x=200+.025x(.011x)=100

We move all terms to the left:

300+.014x-(200+.025x(.011x))=0

We add all the numbers together, and all the variables

.014x-(200+.025x(+.011x))+300=0


We calculate terms in parentheses: -(200+.025x(+.011x)), so:

200+.025x(+.011x)

determiningTheFunctionDomain
.025x(+.011x)+200

We multiply parentheses

x^2+200

Back to the equation:

-(x^2+200)


We get rid of parentheses

-x^2+.014x-200+300=0

We add all the numbers together, and all the variables

-1x^2+.014x+100=0

a = -1; b = .014; c = +100;
Δ = b2-4ac
Δ = .0142-4·(-1)·100
Δ = 400.000196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.014)-\sqrt{400.000196}}{2*-1}=\frac{-0.014-\sqrt{400.000196}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.014)+\sqrt{400.000196}}{2*-1}=\frac{-0.014+\sqrt{400.000196}}{-2}
$