1/3(w-6)=2/9(w+18)

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Solution for 1/3(w-6)=2/9(w+18) equation: 



1/3(w-6)=2/9(w+18)

We move all terms to the left:

1/3(w-6)-(2/9(w+18))=0



Domain of the equation: 3(w-6)!=0

w∈R





Domain of the equation: 9(w+18))!=0

w∈R



We calculate fractions


(9ww/(3(w-6)*9(w+18)))+(-6ww/(3(w-6)*9(w+18)))=0



We calculate terms in parentheses: +(9ww/(3(w-6)*9(w+18))), so:

9ww/(3(w-6)*9(w+18))

We multiply all the terms by the denominator


9ww

Back to the equation:

+(9ww)





We calculate terms in parentheses: +(-6ww/(3(w-6)*9(w+18))), so:

-6ww/(3(w-6)*9(w+18))

We multiply all the terms by the denominator


-6ww

Back to the equation:

+(-6ww)



We get rid of parentheses

9ww-6ww=0

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