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30/(4-x)=3(4+x)
We move all terms to the left:
30/(4-x)-(3(4+x))=0
Domain of the equation: (4-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x!=-4
x!=-4/-1
x!=+4
x∈R
30/(-1x+4)-(3(x+4))=0
We multiply all the terms by the denominator
-((3(x+4)))*(-1x+4)+30=0
We calculate terms in parentheses: -((3(x+4)))*(-1x+4), so:We add all the numbers together, and all the variables
(3(x+4)))*(-1x+4
We add all the numbers together, and all the variables
-1x+(3(x+4)))*(+4
Back to the equation:
-(-1x+(3(x+4)))*(+4)
-(-1x+(3(x+4)))*4+30=0
We move all terms containing x to the left, all other terms to the right
-(-1x+(3(x+4)))*4=-30
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