30+b2=180

Solution for 30+b2=180 equation:

30+b2=180

We move all terms to the left:

30+b2-(180)=0

We add all the numbers together, and all the variables

b^2-150=0

a = 1; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·1·(-150)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*1}=\frac{0-10\sqrt{6}}{2}
=-\frac{10\sqrt{6}}{2}
=-5\sqrt{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*1}=\frac{0+10\sqrt{6}}{2}
=\frac{10\sqrt{6}}{2}
=5\sqrt{6}
$