6(3b-4)=2(b-1)

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Solution for 6(3b-4)=2(b-1) equation: 



6(3b-4)=2(b-1)

We move all terms to the left:

6(3b-4)-(2(b-1))=0

We multiply parentheses

18b-(2(b-1))-24=0



We calculate terms in parentheses: -(2(b-1)), so:

2(b-1)

We multiply parentheses

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

18b-2b+2-24=0

We add all the numbers together, and all the variables

16b-22=0

We move all terms containing b to the left, all other terms to the right

16b=22

b=22/16

b=1+3/8

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