30+3x=7(1-x)-5

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Solution for 30+3x=7(1-x)-5 equation: 



30+3x=7(1-x)-5

We move all terms to the left:

30+3x-(7(1-x)-5)=0

We add all the numbers together, and all the variables

3x-(7(-1x+1)-5)+30=0



We calculate terms in parentheses: -(7(-1x+1)-5), so:

7(-1x+1)-5

We multiply parentheses

-7x+7-5

We add all the numbers together, and all the variables

-7x+2

Back to the equation:

-(-7x+2)



We get rid of parentheses

3x+7x-2+30=0

We add all the numbers together, and all the variables

10x+28=0

We move all terms containing x to the left, all other terms to the right

10x=-28

x=-28/10

x=-2+4/5

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