3/z+12=4/z-3

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Solution for 3/z+12=4/z-3 equation: 



3/z+12=4/z-3

We move all terms to the left:

3/z+12-(4/z-3)=0



Domain of the equation: z!=0

z∈R





Domain of the equation: z-3)!=0

z∈R



We get rid of parentheses

3/z-4/z+3+12=0

We multiply all the terms by the denominator


3*z+12*z+3-4=0

We add all the numbers together, and all the variables

15z-1=0

We move all terms containing z to the left, all other terms to the right

15z=1

z=1/15

z=1/15

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