6(x+2)/3=-(x+1)/2

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Solution for 6(x+2)/3=-(x+1)/2 equation: 



6(x+2)/3=-(x+1)/2

We move all terms to the left:

6(x+2)/3-(-(x+1)/2)=0

We calculate fractions


6x/()+(-(-(x+1)*3)/()=0



We calculate terms in parentheses: +(-(-(x+1)*3)/(), so:

-(-(x+1)*3)/(

We multiply all the terms by the denominator


-(-(x+1)*3)



We calculate terms in parentheses: -(-(x+1)*3), so:

-(x+1)*3

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)



We get rid of parentheses

3x+3

Back to the equation:

+(3x+3)



We get rid of parentheses

6x/()+3x+3=0

We multiply all the terms by the denominator


6x+3x*()+3*()=0

We add all the numbers together, and all the variables

6x+3x*()=0

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