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3/x=4-10x/5x
We move all terms to the left:
3/x-(4-10x/5x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/x-(-10x/5x+4)=0
We get rid of parentheses
3/x+10x/5x-4=0
We calculate fractions
10x^2/5x^2+15x/5x^2-4=0
We multiply all the terms by the denominator
10x^2+15x-4*5x^2=0
Wy multiply elements
10x^2-20x^2+15x=0
We add all the numbers together, and all the variables
-10x^2+15x=0
a = -10; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-10)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-10}=\frac{-30}{-20} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-10}=\frac{0}{-20} =0 $
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