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3/x+2=7/2x
We move all terms to the left:
3/x+2-(7/2x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/x-(+7/2x)+2=0
We get rid of parentheses
3/x-7/2x+2=0
We calculate fractions
6x/2x^2+(-7x)/2x^2+2=0
We multiply all the terms by the denominator
6x+(-7x)+2*2x^2=0
Wy multiply elements
4x^2+6x+(-7x)=0
We get rid of parentheses
4x^2+6x-7x=0
We add all the numbers together, and all the variables
4x^2-1x=0
a = 4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·4·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*4}=\frac{2}{8} =1/4 $
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