27=3(q+4)

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Solution for 27=3(q+4) equation: 



27=3(q+4)

We move all terms to the left:

27-(3(q+4))=0



We calculate terms in parentheses: -(3(q+4)), so:

3(q+4)

We multiply parentheses

3q+12

Back to the equation:

-(3q+12)



We get rid of parentheses

-3q-12+27=0

We add all the numbers together, and all the variables

-3q+15=0

We move all terms containing q to the left, all other terms to the right

-3q=-15

q=-15/-3

q=+5

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