3/x+1=7/2x

Solution for 3/x+1=7/2x equation:

3/x+1=7/2x

We move all terms to the left:

3/x+1-(7/2x)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/x-(+7/2x)+1=0

We get rid of parentheses

3/x-7/2x+1=0

We calculate fractions


6x/2x^2+(-7x)/2x^2+1=0

We multiply all the terms by the denominator


6x+(-7x)+1*2x^2=0

Wy multiply elements

2x^2+6x+(-7x)=0

We get rid of parentheses

2x^2+6x-7x=0

We add all the numbers together, and all the variables

2x^2-1x=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$