(348/12x)+(348/17x)=348

Solution for (348/12x)+(348/17x)=348 equation:

(348/12x)+(348/17x)=348

We move all terms to the left:

(348/12x)+(348/17x)-(348)=0


Domain of the equation: 12x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 17x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+348/12x)+(+348/17x)-348=0

We get rid of parentheses

348/12x+348/17x-348=0

We calculate fractions


5916x/204x^2+4176x/204x^2-348=0

We multiply all the terms by the denominator


5916x+4176x-348*204x^2=0

We add all the numbers together, and all the variables

10092x-348*204x^2=0

Wy multiply elements

-70992x^2+10092x=0

a = -70992; b = 10092; c = 0;
Δ = b2-4ac
Δ = 100922-4·(-70992)·0
Δ = 101848464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{101848464}=10092$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10092)-10092}{2*-70992}=\frac{-20184}{-141984}
=29/204
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10092)+10092}{2*-70992}=\frac{0}{-141984}
=0
$