3/8=(2+x)/32

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Solution for 3/8=(2+x)/32 equation: 



3/8=(2+x)/32

We move all terms to the left:

3/8-((2+x)/32)=0

We add all the numbers together, and all the variables

-((x+2)/32)+3/8=0

We calculate fractions


(-((x+2)*8)/()+()/()=0



We calculate terms in parentheses: +(-((x+2)*8)/()+()/(), so:

-((x+2)*8)/()+()/(

We add all the numbers together, and all the variables

-((x+2)*8)/()+1

We multiply all the terms by the denominator


-((x+2)*8)+1*()



We calculate terms in parentheses: -((x+2)*8), so:

(x+2)*8

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We add all the numbers together, and all the variables

-(8x+16)

We get rid of parentheses

-8x-16

Back to the equation:

+(-8x-16)



We get rid of parentheses

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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