(2x+3)(2x+5)(x-1)(x+2)=30

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Solution for (2x+3)(2x+5)(x-1)(x+2)=30 equation: 



(2x+3)(2x+5)(x-1)(x+2)=30

We move all terms to the left:

(2x+3)(2x+5)(x-1)(x+2)-(30)=0

We multiply parentheses ..

(+4x^2+10x+6x+15)(x-1)(x+2)-30=0

We multiply parentheses ..

(+4x^2+10x+6x+15)(+x^2+2x-1x-2)-30=0

We move all terms containing x to the left, all other terms to the right

(+4x^2+10x+6x+15)(+x^2+2x-1x-2)=30

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