3/7(4x+35)=10

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Solution for 3/7(4x+35)=10 equation: 



3/7(4x+35)=10

We move all terms to the left:

3/7(4x+35)-(10)=0



Domain of the equation: 7(4x+35)!=0

x∈R



We multiply all the terms by the denominator


-10*7(4x+35)+3=0

Wy multiply elements

-70x(4+3=0

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