11h(2h-1)=118

Solution for 11h(2h-1)=118 equation:

11h(2h-1)=118

We move all terms to the left:

11h(2h-1)-(118)=0

We multiply parentheses

22h^2-11h-118=0

a = 22; b = -11; c = -118;
Δ = b2-4ac
Δ = -112-4·22·(-118)
Δ = 10505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{10505}}{2*22}=\frac{11-\sqrt{10505}}{44}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{10505}}{2*22}=\frac{11+\sqrt{10505}}{44}
$