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3/5x+5=-3x-3
We move all terms to the left:
3/5x+5-(-3x-3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x+3x+3+5=0
We multiply all the terms by the denominator
3x*5x+3*5x+5*5x+3=0
Wy multiply elements
15x^2+15x+25x+3=0
We add all the numbers together, and all the variables
15x^2+40x+3=0
a = 15; b = 40; c = +3;
Δ = b2-4ac
Δ = 402-4·15·3
Δ = 1420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1420}=\sqrt{4*355}=\sqrt{4}*\sqrt{355}=2\sqrt{355}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{355}}{2*15}=\frac{-40-2\sqrt{355}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{355}}{2*15}=\frac{-40+2\sqrt{355}}{30} $
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