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(6x-1)(5x+2)=120
We move all terms to the left:
(6x-1)(5x+2)-(120)=0
We multiply parentheses ..
(+30x^2+12x-5x-2)-120=0
We get rid of parentheses
30x^2+12x-5x-2-120=0
We add all the numbers together, and all the variables
30x^2+7x-122=0
a = 30; b = 7; c = -122;
Δ = b2-4ac
Δ = 72-4·30·(-122)
Δ = 14689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{14689}}{2*30}=\frac{-7-\sqrt{14689}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{14689}}{2*30}=\frac{-7+\sqrt{14689}}{60} $
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