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3/5x+1/5=9-6x+11
We move all terms to the left:
3/5x+1/5-(9-6x+11)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-(-6x+20)+1/5=0
We get rid of parentheses
3/5x+6x-20+1/5=0
We calculate fractions
6x-20=0
We move all terms containing x to the left, all other terms to the right
6x=20
x=20/6
x=3+1/3
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