2y(-1/2)=

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Solution for 2y(-1/2)= equation: 



2y(-1/2)=

We move all terms to the left:

2y(-1/2)-()=0

We add all the numbers together, and all the variables

2y(-1/2)=0

We multiply parentheses

-2y^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-4}=0$

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