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3/5p+10=62
We move all terms to the left:
3/5p+10-(62)=0
Domain of the equation: 5p!=0We add all the numbers together, and all the variables
p!=0/5
p!=0
p∈R
3/5p-52=0
We multiply all the terms by the denominator
-52*5p+3=0
Wy multiply elements
-260p+3=0
We move all terms containing p to the left, all other terms to the right
-260p=-3
p=-3/-260
p=3/260
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