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x2/5=12
We move all terms to the left:
x2/5-(12)=0
We multiply all the terms by the denominator
x2-12*5=0
We add all the numbers together, and all the variables
x^2-60=0
a = 1; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·1·(-60)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*1}=\frac{0-4\sqrt{15}}{2} =-\frac{4\sqrt{15}}{2} =-2\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*1}=\frac{0+4\sqrt{15}}{2} =\frac{4\sqrt{15}}{2} =2\sqrt{15} $
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