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3/5n+12=2n-9
We move all terms to the left:
3/5n+12-(2n-9)=0
Domain of the equation: 5n!=0We get rid of parentheses
n!=0/5
n!=0
n∈R
3/5n-2n+9+12=0
We multiply all the terms by the denominator
-2n*5n+9*5n+12*5n+3=0
Wy multiply elements
-10n^2+45n+60n+3=0
We add all the numbers together, and all the variables
-10n^2+105n+3=0
a = -10; b = 105; c = +3;
Δ = b2-4ac
Δ = 1052-4·(-10)·3
Δ = 11145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11145}}{2*-10}=\frac{-105-\sqrt{11145}}{-20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11145}}{2*-10}=\frac{-105+\sqrt{11145}}{-20} $
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