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100+(x-1)+(2x-3)+(3x+4)=101+(5x+5)
We move all terms to the left:
100+(x-1)+(2x-3)+(3x+4)-(101+(5x+5))=0
We get rid of parentheses
x+2x+3x-(101+(5x+5))-1-3+4+100=0
We calculate terms in parentheses: -(101+(5x+5)), so:We add all the numbers together, and all the variables
101+(5x+5)
determiningTheFunctionDomain (5x+5)+101
We get rid of parentheses
5x+5+101
We add all the numbers together, and all the variables
5x+106
Back to the equation:
-(5x+106)
6x-(5x+106)+100=0
We get rid of parentheses
6x-5x-106+100=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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