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3/4y=3-1/2y
We move all terms to the left:
3/4y-(3-1/2y)=0
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 2y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
3/4y-(-1/2y+3)=0
We get rid of parentheses
3/4y+1/2y-3=0
We calculate fractions
6y/8y^2+4y/8y^2-3=0
We multiply all the terms by the denominator
6y+4y-3*8y^2=0
We add all the numbers together, and all the variables
10y-3*8y^2=0
Wy multiply elements
-24y^2+10y=0
a = -24; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-24)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-24}=\frac{-20}{-48} =5/12 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-24}=\frac{0}{-48} =0 $
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