5(6d+4)=6(d-1)+2

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Solution for 5(6d+4)=6(d-1)+2 equation: 



5(6d+4)=6(d-1)+2

We move all terms to the left:

5(6d+4)-(6(d-1)+2)=0

We multiply parentheses

30d-(6(d-1)+2)+20=0



We calculate terms in parentheses: -(6(d-1)+2), so:

6(d-1)+2

We multiply parentheses

6d-6+2

We add all the numbers together, and all the variables

6d-4

Back to the equation:

-(6d-4)



We get rid of parentheses

30d-6d+4+20=0

We add all the numbers together, and all the variables

24d+24=0

We move all terms containing d to the left, all other terms to the right

24d=-24

d=-24/24

d=-1

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