3/4y+5/2y=1

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Solution for 3/4y+5/2y=1 equation:



3/4y+5/2y=1
We move all terms to the left:
3/4y+5/2y-(1)=0
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
We calculate fractions
6y/8y^2+20y/8y^2-1=0
We multiply all the terms by the denominator
6y+20y-1*8y^2=0
We add all the numbers together, and all the variables
26y-1*8y^2=0
Wy multiply elements
-8y^2+26y=0
a = -8; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-8)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-8}=\frac{-52}{-16} =3+1/4 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-8}=\frac{0}{-16} =0 $

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