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3/4x=2/1x-2
We move all terms to the left:
3/4x-(2/1x-2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 1x-2)!=0We get rid of parentheses
x∈R
3/4x-2/1x+2=0
We calculate fractions
3x/4x^2+(-8x)/4x^2+2=0
We multiply all the terms by the denominator
3x+(-8x)+2*4x^2=0
Wy multiply elements
8x^2+3x+(-8x)=0
We get rid of parentheses
8x^2+3x-8x=0
We add all the numbers together, and all the variables
8x^2-5x=0
a = 8; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·8·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*8}=\frac{10}{16} =5/8 $
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